922. Sort Array By Parity II - LeetCode Solution

class Solution:
    def sortArrayByParityII(self, A: List[int]) -> List[int]:
        
        d = [0] * len(A)
        
        even = 0
        odd =1
        
        for i in range(len(A)):
            if A[i]%2 ==0 :
                d[even] = A[i]
                even+=2
            else:
                d[odd] = A[i]
                odd+=2
                
        
        return d